(3x+4)/(x^2+9x+20)=0

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Solution for (3x+4)/(x^2+9x+20)=0 equation: 


D( x )

x^2+9*x+20 = 0

x^2+9*x+20 = 0

x^2+9*x+20 = 0

x^2+9*x+20 = 0

DELTA = 9^2-(1*4*20)

DELTA = 1

DELTA > 0

x = (1^(1/2)-9)/(1*2) or x = (-1^(1/2)-9)/(1*2)

x = -4 or x = -5

x in (-oo:-5) U (-5:-4) U (-4:+oo)

(3*x+4)/(x^2+9*x+20) = 0

x^2+9*x+20 = 0

x^2+9*x+20 = 0

DELTA = 9^2-(1*4*20)

DELTA = 1

DELTA > 0

x = (1^(1/2)-9)/(1*2) or x = (-1^(1/2)-9)/(1*2)

x = -4 or x = -5

(x+5)*(x+4) = 0

(3*x+4)/((x+5)*(x+4)) = 0

3*x+4 = 0 // - 4

3*x = -4 // : 3

x = -4/3

x = -4/3

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